Question

Find the points of trisection of the line segment joining the points (- 2, 1) and (7, 4)​

Answer 1

Answer:

X1=-2,x2=7; y1 = 1,y2 = 4

Step-by-step explanation:

Now u can take x3 and y 3 as x and y

Formula x =x1+x2+x3/3

Y =y1+y2+y3/3

Answer 2

P (1 ,2) Q( 4,3)

Step-by-step explanation:

A (-2,1), B ( 7,4)

let point P and Q be the points of trisection of the line segment joining the points A and B .

point P and Q divide line segment AB into three parts

AP = PQ = QB .......(1)

AP / PB = AP / PQ+QB = AP /AP +AP = AP/2AP = 1/2---(from 1)

point P divides seg AB in the ratio 1:2.

x co-ordinate of point P

= 1×7+2×(-2)/1+2

= 7-4/3

= 1

y co- ordinate of point P

= 1× 4+2×1/1+2

= 4+2/3

= 2

P (1,2)

point Q divide seg AB in the ratio 2:1

x co-ordinate of point Q

= 2×7+1×(-2)/2+1

= 14-2/3

= 4

y co ordinate of point Q

= 2×4+1×1/2+1

=8+1/3

= 3

Q( 4,3)