Question

Find the points of trisection of the line segment joining (7, 5) and (-2, -1).​

Answer 1

Answer:

C(4,3) and D(1,1)

Step-by-step explanation:

let c(x1,y1) and D(x2y2)divides line segment joining AB in 3 equal parts.

Points D (x2,y2) divides AB in the ratio 2:1

D(x2,y2) = [2*-2 + 7*1/2+1 , 2*-1 +1*5/2+1]

               =[-4+7/3 , -2+5/3]

               =[3/3 ,3/3]

               =(1,1)

C is the mid point of AD.

C(x1,y1)=[1*1+7*1/2 , 1*1+5*1/2]

            =[8/2 , 6/2]

            = (4,3)