Find the points on the curve y=x³ at which the slope of tangent is equal to the y co-ordinate of the point.
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Heya mate here is your answer is in image :
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let the point be (h,k) on the plane
when slope of tangent at (h,k) = y coordinate of (h,k)
that is dy/dx (h, k) = k
Given y = x ³
Differentiating with respect to x, then
dy/dx = 3x²
Hence, slope of tangent at (h, k) is
dy/dx(h, k) = 3h²
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