Question

Find the points on the line 3x-4y-1=0 which are at a distance of 5 units from the point (3,2)

Answer 1

Answer:

Step-by-step explanation:

take the point as (x1,y1) now this point lies on the given line so satisfies it i.e

$3x_{1}-4y_{1}-1=0$

from this find x1 or y1 (as you wish )

$x_1=\frac{1+4y_1}{3}$

now the point will be ($\frac{1+4y_1}{3},y_1$)

apply distance formula in this point and (3,2) put that distance equal to 5 and solve for y1 then find x1