Question

find the points on the line 4x-3y-10=0 which are at a distance of 5 units from the point (1,-2)

Answer 1

Answer:

Any point on the line is (t,4−t)

According to the question,

4

2

+3

2

∣4t+3(4−t)−10∣

=1

⇒∣t+2∣=5

⇒t+2=±5

⇒t=3−7

Hence, the required points are (3,1) and (−7,11).

Answer 2

Answer:

I can't understand it so sorry