find the points on the line x+y=5 that lie at the distance 2unit from the line 4x+3y -12=0
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Step-by-step explanation:
Find all points on x + y = 4 that lie at a unit distance from the line 4x + 3y - 10 = 0
Note that the co-ordinates of an arbitrary point on x + y = 4 can be obtained by putting x = t (or y = t) and then obtaining y (or x) from the equation of the line where t is a parameter
Putting x = t in the equation x + y = 4 of the given line we obtain y = 4 - t So co-ordinates of an arbitrary point on the given line are P(t, 4 - t) Let P(t, 4 - t) be the required point Then distance of P from the line 4x + 3y - 10 = 0 is unity i.e.
⇒
∣
∣
∣
∣
∣
4
2
+3
2
4t+3(4−t)−10
∣
∣
∣
∣
∣
=1⇒∣t+2∣=5
⇒t+2=±5 ⇒ t=−7 or t=3.
Hence the required points are (−7,11) or (3,1)
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