find the points on the x axis , which are at a distance of 2 root 6 units from the point (1,-2,3)
Answers
Given : the points on the x axis , which are at a distance of 2 root 6 units from the point (1,-2,3)
To Find : the points on the x axis
Solution:
Points on x axis = ( x , 0 , 0) as y and z coordinate will be zero
Distance of ( x , 0 , 0) from (1,-2,3) is 2√6
=> √(x - 1)² + (0 - (-2))² + ( 0 - 3)² = ( 2√6)²
=> (x - 1)² + 4 + 9 = 24
=> (x - 1)² = 11
=> (x - 1) = ±√11
=> x = 1 ±√11
Points on x axis ( 1 ±√11 , 0 , 0) which are at a distance of 2 root 6 units from the point (1,-2,3)
( 1 +√11 , 0 , 0) and ( 1 -√11 , 0 , 0)
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