Find the points on the y-axis which are at a distance of 3 units from the point (2,3,-1)?
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Given : Points on the y-axis at a distance of 3 units from the point (2,3,-1)
To Find : Points
Solution:
Points on y axis = ( 0 , y , 0)
as x and z coordinate will be zero
distance of 3 units from the point (2,3,-1)
=> √(2 - 0)² + ( 3 - y)² + (-1 - 0)² = 3
Squaring both sides
=> 4 + ( 3 - y)² + 1 + 9
=> ( 3 - y)² = 4
=> y² - 6y + 9 = 4
=> y² - 6y + 5 = 0
=> (y - 1)(y - 5) = 0
=> y = 1 , y = 5
Points on y axis = ( 0 , 1 , 0) or ( 0 , 5 , 0 ) are at a distance of 3 units from the point (2,3,-1)
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