Find the points on x axis which are at a distance of 5 units from (5,-3)
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Answered by
96
as it is a point on x axis
then the coordinates are [ x, 0 ]
squaring
[5-x]square + [-3-0]square= 25
25-10x+x square+9= 25
x square - 10x +9=0
b2-4ac
root of 100-36
i.e 8
10+8/2 or 10-8/2
x is 9 or 1
therefore coordinates are [9,0] or [1,0]
pls mark this as brainliest
then the coordinates are [ x, 0 ]
squaring
[5-x]square + [-3-0]square= 25
25-10x+x square+9= 25
x square - 10x +9=0
b2-4ac
root of 100-36
i.e 8
10+8/2 or 10-8/2
x is 9 or 1
therefore coordinates are [9,0] or [1,0]
pls mark this as brainliest
tanushrinambiap42rg5:
your welcome
Answered by
93
The point is on X- axis , y=0
THE POINT ON X-axis
(x,0)
THE DISTANCE BETWEEN THE POINTS
(x,0) & ( 5,-3) is 5 units.
Therefore,
the coordinates are (1,0) or (9,0)
hope this helps!!!
THE POINT ON X-axis
(x,0)
THE DISTANCE BETWEEN THE POINTS
(x,0) & ( 5,-3) is 5 units.
Therefore,
the coordinates are (1,0) or (9,0)
hope this helps!!!
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