Question

find the points on X-axis which is equidistant from P(2,-5) and Q(-2,9).
ans this question as fast as u can.......​

Answer 1

Answer:

(-7,0)

Step-by-step explanation:

since point is one x axis so it's y coordinate must be zero. let the point be (x,0)

given its equidistant to (2,-5) and (-2,9)

therefore

√(2-x)²+(-5-0))²=√(-2-x)²+(9-0)²

x²+4-4x+25=4+x²+4x+81

-8x+25=81

-8x=81-25

-8x=56

x=-7

hence the point is (-7,0)