Question

find the points on x axis which is equidistant from the points (2,-2) and (-4,2)​

Answer 1

Step-by-step explanation:

let's call the point (2,-2) as A, (-4,2) as B, They are located on the x-axis and this as C, suppose they are making a triangle, as there will two coordinate on the x-axis, so there will two numbers which ate unknown, let's call them x,y. we know that y= 0. so we have to only find x

fas the question says, we get that

AC = BC

(AC)²=(BC)²

(x1-x2)²+(y1-y2)= (x1-x2)²+(y1-y2)

(2-x)²+((-2)-0)² = ((-4)-x)²+(2-0)²

(4+x²-4x)+4 = (16+x²+8x)+4

-4x+8+x²=20+8x+x²

-12x=12

x=-1