Find the points on x-axis which lie on the curve
16x² + 25y²= 400
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Answer:
Step-by-step explanation:
let A and B be the intersection of the the curve 16x^2 + 25y^2 = 400 with the x-axis. then y = 0 and therefore
16x^2 = 400 and thus x^2 = 25 and consequently x = +-5. finally
A(- 5 , 0) and B(5 , 0).
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