Question

find the points on y axis which are at a distance of 5 units from A(4,3)​

Answer 1

Answer:

hey friend here is your answer

Let the points be (0,y)

Distance is B⟹

25+(y−7)

2

=B

y=7±

B

2

−25

Points are (0,7+

B

2

−25

) and (0,7−

B

2

−25)