Question

Find the points where the graph of the equation 3x + 4y = 12. Cuts the x - axis and y- axis

Answer 1

this is the solution

Answer 2

Answer:

Graph of the equation 3x+4y = 12 cuts x-axis at (4,0) and y - axis at (0,3).

Step-by-step explanation:

Given equation 3x+4y=12 ---(1)

$Write \: the \: equation \: into \: intercept \\form \:$

/* Divide each term by 2, we get */

$\implies \frac{3x}{12}+\frac{4y}{12}=\frac{12}{12}$

$\implies \frac{x}{4}+\frac{y}{3}=1$

Here ,

x-intercept (a) = 4 ,

y-intercept (b) = 3

Therefore,

Graph of the equation 3x+4y = 12 cuts x-axis at (4,0) and y - axis at (0,3).

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