find the points where the graph of the equation 3x+4y=12 cuts the x-axis and the y-axis
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The graph of 3x+4y = 12 cuts x-axis at (4,0) & y- axis at (0,-3) .
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1
Answer:
-> 4y = 24 -3x
let "x" = 0:
-> 4y = 24 - 3 × 0
-> 4y = 24
-> y = 6
-> (0,6) = Points:
-> Let "x" = 4
-> 4y = 24 - 3 (4)
-> 4y = 24 -12
-> y = 12 / 4
-> y = 3
-> (4,3) = Points:
-> x = -4
-> 4y = 24 - 3v ( -4 )
-> 4y = 24 + 12
-> y = 36 / 4
-> y=9
(-4,9) = Points:
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