Question

find the points where the line represented by the equation 2x+3y=11 cuts y axis

Answer 1

given equation 2x + 3y = 11
Now, every point in y axis has abcisaa 0.
Therefore point is (0,y)
For, x=0
y=11/3

point is (0, 11/3)

Answer 2

Concept:

The intercept form of the equation of a line is x/a + y/b = 1.

Where, a = x-intercept and, b = y-intercept

Given:

2x + 3y = 11

Find:

We are asked to find the points where the line represented by the equation 2x + 3y = 11 cuts the y-axis.

Solution:

We have,

2x + 3y = 11

Now,

To find the points for the y-axis,

We have to rewrite the given equation in the  intercept form,

i.e.

2x + 3y = 11

Now, divide the given equation by 11,

i.e.

2x/11 + 3y/11 = 11/11

We get,

2x/11 + 3y/11 = 1

Now,

We can rewrite above equation as ;

x/(11/2) + y/(11/3) = 1

So, according to the  intercept form x/a + y/b = 1,

i.e.

x = 11/2

y = 11/3

Hence we can say that the points where the line represented by the equation 2x + 3y = 11 cuts the y-axis are x = 11/2 and y = 11/3.

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