find the points which are at a distance of root 10 from the point (4,3),given that the ordinate of point are twice the abscissa
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Answer:
HELLO ARMY
Step-by-step explanation:
Let the point A be (x,2x)
Now, using distance formula between (x,2x) and (4,3)
⇒
(4−x)
2
+(3−2x)
2
=
10
Squaring both sides we get,
⇒ (4−x)
2
+(3−2x)
2
=(
10
)
2
⇒ 16−8x+x
2
+9−12x+4x
2
=10
⇒ 5x
2
−20x+15=0
⇒ x
2
−4x+3=0
⇒ x
2
−3x−x+3=0
⇒ x(x−3)−1(x−3)=0
⇒ (x−3)(x−1)=0
⇒ x−3=0 and x−1=0
∴ x=3,1
Co-ordinates when x=3
⇒ (x,2x)=(3,6)
Co-ordinates when x=1
⇒ (x,2x)=(1,2)
HOPE I HELPED YOUUU
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