Question

Find the points which divide the join of (2,1) and (3,6) internally in the ratio 2:3​

Answer 1

Answer:

Step-by-step explanation:

Using the section formula, if a point (x,y) divides the line joining the points (x  

1

​

,y  

1

​

) and (x  

2

​

,y  

2

​

) in the ratio m:n, then  

(x,y)=(  

m+n

mx  

2

​

+nx  

1

​

 

​

,  

m+n

my  

2

​

+ny  

1

​

 

​

)

Since, point P divides the join of (2,1) and (-3,6) in the ratio 2 : 3.

So, coordinates of P are :

(  

5

2(−3)+3(2)

​

,  

5

2(6)+3(1)

​

)=(0,3)

If P lies on the given line, then it must satisfy the given equation of the line.

Therefore,

x−5y+15=0

0−15+15=0

0=0

Hence, point P lies on the given line.