Find the polar coordinates of the point ( 1 , √3)
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x=−
3
and y=1
r=
x
2
+y
2
=
(−
3
)
2
+1
2
=2
θ=tan
−1
(
x
y
)=tan
−1
(−
3
1
)=−
6
π
Thus, the polar co-ordinates are (2,−
6
π
)
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