find the polar equation for circle x²+(y-3)²=9
Answers
Answered by
1
Step-by-step explanation:
Given:
x
2
+
(
y
−
3
)
2
=
9
expand the square:
x
2
+
y
2
−
6
y
+
9
=
9
Substitute
r
2
for
x
2
+
y
2
:
r
2
−
6
y
=
0
Substitute
r
sin
(
θ
)
for y:
r
2
−
6
r
sin
(
θ
)
=
0
We can discard a factor of r because the root
r
=
0
is duplicated at
θ
=
0
r
−
6
sin
(
θ
)
=
0
r
=
6
sin
(
θ
)
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