find the polar form of -2i
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Because the real part (a) of the complex number is zero, you cannot use
θ
=
tan
−
1
(
b
a
)
; you must know that the angle is either
π
2
or
3
π
2
. Because the sign of the complex part is negative, you must know that this makes the angle the latter,
3
π
2
.
θ
=
3
π
2
hope it helps u...mate...
You can see that the magnitude is 2.
The polar form is:
2
(
cos
(
3
π
2
)
+
i
sin
(
3
π
2
)
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