Question

find the polar form of (-3+√3i)​

Answer 1

$(cos\frac{\pi }{6} + isin\frac{\pi }{6})$

Step-by-step explanation:

Step 1: Given , (-3+√3i)​

let, rcosФ=-3 and rsinФ=√3i

on squaring and adding we get

r²cos² θ+r²sin² θ=3+1

r²=4

r=2.

​Step 2:

cosФ=$\frac{\sqrt{3} }{2}$

Ф=$\frac{\pi }{6}$

therefore poler form is$(cos\frac{\pi }{6} + isin\frac{\pi }{6})$