Question

Find the polynomial having two zeroes ae -3/2 and 3/5

Answer 1

hope it helps....................

Answer 2

Answer:

$10x^{2}-9x-9=0$

Step-by-step explanation:

Given : Zeroes are -3/2 and 3/5

To Find: Find the polynomial

Solution:

formula of polynomial = $x^{2}+(\alpha+\beta)x+\alpha\beta=0$

Where α = -3/2

β = 3/5

so putting values in formula:

$x^{2}+(\frac{-3}{2} +\frac{3}{5} )x+(\frac{-3}{2}* \frac{3}{5}) =0$

$x^{2}+\frac{-9}{10}x+\frac{-9}{10}=0$

$10x^{2}-9x-9=0$

Hence the required expression is $10x^{2}-9x-9=0$