Find the polynomial of degree 2 in x, when divided by x + 1 , x + 2 and x + 3 , leaves remainders 1, 4, and 3 respectively. Find the polynomial.
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Let polynomial be ax^2 + bx + c
According to remainder th f(-1)=1
Ie a-b+ c=1
And 4a-2b + c= 4
And 9a-3b+c = 3
Solve now
According to remainder th f(-1)=1
Ie a-b+ c=1
And 4a-2b + c= 4
And 9a-3b+c = 3
Solve now
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