Find the polynomial of the following quadratic polynonual
the relationship between groes & co-effecents
x² + 7x + 10
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Step-by-step explanation:
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Given :
- The zeroes of the quadratic polynomial = x² + 7x + 10.
To Verify :
- The relationship between zeroes & co-effecents.
Step-by-step explanation :
We have,
p(x) = x² + 7x + 10
p(x) = x² + 5x + 2x + 10
p(x) = x(x + 5) + 2(x + 5)
p(x) = (x + 5) (x + 2)
So, the value of p(x) = x² + 7x + 10 is zeroes when (x + 5) = 0 or (x + 2) = 0
i.e., when x = - 5 or - 2
∴ The zeroes of x² + 7x + 10 are - 5 or - 2.
Now,
Sum of zeroes = ( -5 ) + ( -2 )
= - 7
= - 7/1
= - ( Coefficient of x) / Coefficient of x²
Product of zeroes = ( - 5) ( -2)
= 10
= 10/1
= Constant term/ Coefficient of x²
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