Find the polynomial which when finished by(x–3)gives a quotient the
x²–2x+1andremainder5.
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a=bq+r
a= (–x² + x – 1) × (x–2)+3
a=–x³ + x² – x + 2x²– 2x + 2 + 3
[ a=–x³ + 3x² – 3x + 5 ]
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