find the polynomial who zeroes are 3 -2 and -3
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Answer:
since it has three zeroes so it is a cubic polynomial,
now sum of zeroes= -2
product of zeroes taken two at a time
=ab+bc+ca
= 3×(-2)+(-2)×(-3)+(-3)×3
= -6+6-9
= -9
product of zeroes= 3×(-2)×(-3)
= 18
now for a cubic polynomial standard form is
f(x)= k{ x^3-(sum of zeroes)x+(product of zeroes taken two at a time)x^2-(product of zeroes)}
f(x)= x^3-(-2)x^2+(-9)x-(18)
f(x)= x^3+2x^2-9x-18
hope it helps you
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