Question

Find the polynomial whose roots are
; sq rt of 2 and 1/3

Answer 1

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Here is your answer

$given$

$\alpha = 2$

$\beta = 1 \div 3$

We know that

$\alpha + \beta = - b \div a$

»2+(1/3)

»6+1/3

7/3

$\alpha \beta = c \div a$

2(1/3)

2/3

To find the quadratic equation

$k(x {}^{2} -( \alpha + \beta) x + \alpha \beta )$

$k(x {}^{2} - 7 \div 3 + 2 \div 3)$

$k(3x {}^{2} - 7x + 2 \div 3)$

Let k=3

Hence the quadratic equation

$3x { }^{2} - 7x + 2$

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