Find the Polynomial whose Sum and Product of Zeroes are √(3)/4 and 1/√(2) Respectively.
Answers
Answered by
0
alpha +beta=√3/4
alpha ×beta=1/√2
k(x2+(alpha+beta)x+alpha×beta)
k(x2+√3x/4+1/√2)
alpha ×beta=1/√2
k(x2+(alpha+beta)x+alpha×beta)
k(x2+√3x/4+1/√2)
Answered by
0
Hey
Here is your answer,
Quadratic polynomial = x^2 - (Sum of zeroes ) x + product of zeroes
= X^2 - (√3/4)x + 1/√2
= X^2 - √6 x +4 /4√2
=4√2x^2 - √6x + 4
Hope it helps you!
Here is your answer,
Quadratic polynomial = x^2 - (Sum of zeroes ) x + product of zeroes
= X^2 - (√3/4)x + 1/√2
= X^2 - √6 x +4 /4√2
=4√2x^2 - √6x + 4
Hope it helps you!
Similar questions
Science,
7 months ago
India Languages,
7 months ago
Biology,
7 months ago
Math,
1 year ago
Math,
1 year ago