Question

Find the polynomial whose two zeros are 3-root5 and 3+root5

Answer 1

Step-by-step explanation:

The Quadratic polynomial is -

x² - (Sum of zeroes)x + (product of zeroes) = 0

x² - (3-√5 + 3+√5)x + (3-√5)(3+√5) = 0

x² - (6)x + (9 - 5) = 0

x² - 6x + 4 = 0

Answer 2

Answer:

$given \: \: \alpha = 3 - \sqrt{5} \\ \: \: \: \: \: \: \: \: \: \: \: \: \beta = 3 + \sqrt{5} \\ = > {x}^{2} - (3 - \sqrt{5} + 3 + \sqrt{5} )x + (3 - \sqrt{5} ) \times (3 + \sqrt{5} ) \\ = > {x}^{2} - 9x + 4 \\ = > answer$

this is your answer mate