Find the polynomial whose zeroes are 3+root 2 and 3-root 2
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Answer:
Step-by-step explanation: Let a and b be the zeroes....
1. Sum of zeroes= 3+root2+3-root2
=> 6....
2. Product of zeroes= (3+root2)(3-root2)
=> 9-2= 7.....
So, the quadratic polynomial is K(X^2-(a+b)x+ab)
=> K(X^2-6x+7) where k is any non-zero real no........
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