Find the polynomial whose zeroes are 4±√2÷2
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Step-by-step explanation:
let a and b are the zeroes of the polynomial.
a=4+√2/2 and b=4-√2/2
sum of zeroes=4+√2/2+4-√2/2
a+b=8
product of zeroes=(4+√2/2) (4√-2/2)
=(4^2-(√2/2^2)
=16-2/4
=16-1/2
ab=31/2
Required polynomial = k{x^2-(a+b)x+ab}
k{x^2-8x+31/2}
put k =2
2x^2-16x+31
hope it helps u
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