Question

find
the
polynomial whose zeroes are 6,-6 .​

Answer 1

Step-by-step explanation:

$sum \: of \: product( \alpha + \beta ) = 6$

$product \: of \: zero( \alpha \beta ) = - 6$

$quadratic \: polynomial = x ^{2} - ( \alpha + \beta )x + \alpha \beta$

${x}^{2} - 6x - 6$

Answer 2

→the zereos are= 6, -6

so,

→sum of the zeroes = 6+(-6)

=6-6

=0

→Product of zeroes = 6×(-6)

= -36

then,

→required polynomial is= $=x^2$- (sum of the zeroes)x+(product of the zeroes)

$=x^{2}-(0)x+(-36)\\=x^{2}-36$

$=x^{2}-36$ is the required polynomial