Question

find the polynomial whose zeroes are double the zeroes of polynomial is x^2-x-42​

Answer 1

${\tt{\pink{\underline{\underline{\huge{Answer:}}}}}}$

$\implies\sf{x}^{2} - x - 42 = 0$

$\implies\sf {x}^{2} - 7x + 6x - 42 = 0$

$\implies\sf \: x(x - 7) + 6(x - 7) = 0$

$\implies\sf(x + 6) = 0 \: \: or \: \: (x - 7) = 0$

$\implies\sf \: x = - 6 \: \: or \: \: x = 7$

_________________________________

Answer 2

Answer:

upper answer is correct