Question

"find the polynomial whose zeroes are reciprocal of zeroes of 2x^2+3x-6."solve this question i will mark you brainelist​

Answer 1

OLA!!❤

Let P(x) = 2x2 + 3x - 6.

Given that the polynomial whose zeroes are reciprocal of the zeroes of the polynomial

let x = 1 / x

P(1 / x) = 0

= 2(1 / x)2 + 3(1 / x) - 6 = 0

= 2 + 3x - 6x2 = 0

∴ The reciprocal of the zeroes of the polynomial 6x2 -3x - 2 = 0

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Tysm❤

Answer 2

In QUESTION we are given 2x²+3x–6

So, let's take it as f(x) = 2x²+3x–6

In QUESTION it's also given that polynomial whose zeroes are reciprocal of the zeroes of the f(x)

So, A/c take

$x = \frac{1}{x}$

So, From here We can put this value of "x" in f(x)

.........

$2( { \frac{1}{x} })^{2} + 3( \frac{1}{x} ) - 6 = 0$

$\frac{2 + 3x - 6 {x}^{2} }{ {x}^{2} } = 0$

$2 + 3x - 6 {x}^{2} = 0$

$6 {x}^{2} - 3x - 2 = 0$

The reciprocal of the Zeroes of the Polynomial↑↑↑↑↑