Question

Find the polynomial whose zeros are 2 alpha + 3 Beta 3 alpha + 2 Beta

Answer 1

Answer:

Given Equation is f(x) = ma - nx - 3x².

Given that x + a is a factor of ma - nx - 3x².

⇒ x + a = 0

⇒ x = -a

Substitute x = -a, we get

f(-a) = ma - n(-a) - 3(-a)²

⇒ 0 = ma + na - 3a²

⇒ ma + na - 3a² = 0

⇒ 3a² - ma - na = 0

⇒ 3a² - a(m + n) = 0

⇒ 3a² = a(m + n)

⇒ 3a = m + n

⇒ a = (m + n)/3

Read more on Brainly.in - https://brainly.in/question/9749643#readmore

Step-by-step explanation: