Question

Find the polynomial whose zeros are√2and-3

Answer 1

Step-by-step explanation:

the polynomial is,

(x-√2)(x+3)

= x^2 + 3x - √2x - 3√2

= x^2 + (3 - √2)x - 3√2

Answer 2

Answer:

x²-(√2-3)x-3√2

Step-by-step explanation:

Sum of Roots=$\sqrt{2}+(-3)$=$\sqrt{2}-3$

Product of Roots=$(\sqrt{2})(-3)$=$-3\sqrt{2}$

Skeletal Quadratic Equation:-

x²-(sum of roots)x+(product of roots)

x²-(√2-3)x-3√2