Find the polynomial whose zeros are root 3 by 2 and minus root 3 by 2
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4
Let α=√3/2
β=-√3/2
When roots are given, a quadratic equation is always
x²+(α+β)x+αβ
Substituting values,
x²+(√3/2-√3/2)x+(√3/2)×(-√3/2)
x²-3/4
β=-√3/2
When roots are given, a quadratic equation is always
x²+(α+β)x+αβ
Substituting values,
x²+(√3/2-√3/2)x+(√3/2)×(-√3/2)
x²-3/4
faizaankhanpatp3bt9p:
4 should be brought up
Answered by
2
x² - ( X + Y ) + XY ---------- 1
so substituting the roots in 1 we get
4x² + 0x - 3 = 0
so substituting the roots in 1 we get
4x² + 0x - 3 = 0
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