Question

find the polynomials p (x) = x square -3 x+4 p(0) = p-(1) -1 (1) p(-2) p(2) ​

Answer 1

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Given polynomial is p(x)=x 2 −3x+2Replace x by 0, we getp(0)=(0) 2 −3(0)+2⇒p(0)=0+0+2⇒p(0)=2Replace x by 1, we getp(1)=(1) 2 −3(1)+2⇒p(1)=1−3+2⇒p(1)=0Replace x by 2, we getp(2)=(2) 2 −3(2)+2⇒p(2)=4−6+2⇒p(2)=0

${ \huge \color{yellow}{ \boxed{ \fcolorbox{yellow}{purple}{hope \: this \: helps}}}}$