Math, asked by jayanth6, 1 year ago

find the population of a city after 2 years which is at present 12 lakh , if the rate of increase is 4%.

Answers

Answered by Incredible29
633
HEY
HERE'S YOUR ANSWER!!

Present population = 12 lakh = 1200000
Time = 2 years
Rate of increase = 4%
Therefore, population after 2 years is
= present population(1 + r/100)²
= 1200000 (1 + 4/100)²
= 1200000 * (104/100)²
= 1200000 * 104/100 * 104/100
= 120 * 104 * 104
= 1297920. {ANSWER}

hope it helps!!

Incredible29: plz follow if u lyk my answer
jayanth6: no thats wrong answer please tell correct answer because having exam maths please tell
Incredible29: so sorry...by mistake i depreciated the rate...but i corrected it
Incredible29: check once again
jayanth6: thanks
Incredible29: welcome
Answered by siddhartharao77
180
Formula is a =  p(1+r/100)^n             ------------------ (i)

Given p = 1200000, r = 4, n = 2

On submitting values in (i) we get, 

 a = 1200000(1+4/100)^2

    =  1200000(1 + 1/25)^2

    = 1200000(26/25)^2

    = 1200000 * 26/25 * 26/25

    = 1248000 * 26/25

    = 1297920


Hope this helps! 


jayanth6: thanks for helping be in touch with me
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