find the population of a city after 2 years which is at present 12 lakh , if the rate of increase is 4%.
Answers
Answered by
633
HEY
HERE'S YOUR ANSWER!!
Present population = 12 lakh = 1200000
Time = 2 years
Rate of increase = 4%
Therefore, population after 2 years is
= present population(1 + r/100)²
= 1200000 (1 + 4/100)²
= 1200000 * (104/100)²
= 1200000 * 104/100 * 104/100
= 120 * 104 * 104
= 1297920. {ANSWER}
hope it helps!!
HERE'S YOUR ANSWER!!
Present population = 12 lakh = 1200000
Time = 2 years
Rate of increase = 4%
Therefore, population after 2 years is
= present population(1 + r/100)²
= 1200000 (1 + 4/100)²
= 1200000 * (104/100)²
= 1200000 * 104/100 * 104/100
= 120 * 104 * 104
= 1297920. {ANSWER}
hope it helps!!
Incredible29:
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Answered by
180
Formula is a = p(1+r/100)^n ------------------ (i)
Given p = 1200000, r = 4, n = 2
On submitting values in (i) we get,
a = 1200000(1+4/100)^2
= 1200000(1 + 1/25)^2
= 1200000(26/25)^2
= 1200000 * 26/25 * 26/25
= 1248000 * 26/25
= 1297920
Hope this helps!
Given p = 1200000, r = 4, n = 2
On submitting values in (i) we get,
a = 1200000(1+4/100)^2
= 1200000(1 + 1/25)^2
= 1200000(26/25)^2
= 1200000 * 26/25 * 26/25
= 1248000 * 26/25
= 1297920
Hope this helps!
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