Question

Find the position and naluee
double points on the curve
(x-2)² = y(y-1) ^2

Answer 1

Answer:

y=(x−2)2

dxdy=dxd((x−2)2)=2(x−2)

∴ slope of tangent =2x−4

Slope of line joining (2,0)and (4,4) =4−24−0=2

The tangent is parallel to this line

∴ their slopes are equal

2x−4=2 ⇒2x=6

∴x=3

and y=(3−2)2=1

Thus the point is (3,1)

Step-by-step explanation:

Mark as brainiest

Follow me