Science, asked by divya54600, 9 months ago

Find the position and nature of the image formed when an object is placed at a distance of 5cm
from a concave mirror of focal length 15cm. What is it's magnification​
plz tell fast

Answers

Answered by Anonymous
68

Given :

➳ Distance of object = 5cm

➳ Focal length = 15cm

➳ Type of mirror : Concave

To Find :

  • Distance of image
  • Magnification
  • Nature of image

SoluTion :

Distance of image :

⟶ 1/u + 1/v = 1/f

⟶ 1/(-5) + 1/v = 1/(-15)

⟶ 1/v = -1/15 + 1/5

⟶ 1/v = (-1 + 3)/15

⟶ 1/v = 2/15

v = 7.5 cm

Magnification :

➠ m = -v / u

➠ m = -7.5/-5

m = 1.5

Nature of image :

  • Virtual
  • Erect
  • Enlarged
Answered by xrewjack
28

Answer:

here

     u= - 5cm

     f=-15cm( since,mirror is concave)

    now,

     1 /v + 1/u =1/f

 ⇒1/v - 1/ 5 =1/-15

 ⇒1/v =-1/15 + 1/5

  ⇒1/v= - 1+3/15

   ⇒1/v =2/15

    ⇒v= 15/2

     ⇒v=+7.5 cm

∴ the image is formed 7.5 cm behind the mirror .

again,

      m=-v/u

          =-(7.5/-5)

           =+1.5

∴ nature is virtual and errect

good luck

Explanation:

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