Question

Find the position and nature of the image of an object 5cm high and 10cm in front of a convex lens of
focal length 6cm.

Answer 1

hence the nature of image formed will be as follows:

• of height 15 cm

• real and inverted

• larger than object

Answer 2

Reference of diagram is given below:-

Given:-

Length(AB/CD) = 4 × breadth

Area of rectangle = 1600 sq.m

To find:-

Diagonal of rectangle (AC/BD) =?

Now, let breadth be x m and length be 4x m.

\begin{lgathered}\rm We \:know, \\\\\dag \: {\boxed{\rm{Area \: of \: rectangle = Length \times Breadth }}}\end{lgathered}

Weknow,

†

Areaofrectangle=Length×Breadth

A/Q,

\begin{lgathered}\dashrightarrow\sf 4x \times x = 1600 \\\\\dashrightarrow\sf 4x^2 = 1600 \\\\\dashrightarrow\sf x^2 = 1600/4 \\\\\dashrightarrow\sf x^2 = 400 \\\\\dashrightarrow\sf x = \sqrt{400} \\\\\dashrightarrow\sf x ={\boxed{\sf\green{20 \: m }}}\end{lgathered}

⇢4x×x=1600

⇢4x

2

=1600

⇢x

2

=1600/4

⇢x

2

=400

⇢x=

400

⇢x=

20m

\dashrightarrow\sf Breadth = x = {\boxed{\sf\green{20\: m }}}⇢Breadth=x=

20m