Question

find the position and time where kinetic become 3/4 of total energy​

Answer 1

Answer:

As per,

KE=

100

75

E=

100

75

×

2

1

ma

2

ω

2

2

1

ma

2

ω

2

cos

2

ωt=

100

75

×

2

1

ma

2

ω

2

cos

2

ωt=

4

3

cosωt=

2

3

=cos

6

π

or ωt=

6

π

⇒t=

6π

π

=

6

1

s