Find the position, nature and height of the image formed by a concave mirror of focal length 20cm when a 5cm size object is placed in front of the mirror at i) 20cm ii) 40cm
Answers
Answered by
0
It is given that,
It is given that,Focal length
It is given that,Focal lengthf=−20cm
It is given that,Focal lengthf=−20cmh i =3ho
It is given that,Focal lengthf=−20cmh i =3hoThe image is three times the size of the object.
So there are two cases.
Case 1. For real image
Case 1. For real imagem=-v/u=-3
Case 1. For real imagem=-v/u=-3v=3u
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/u
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual image
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3u
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3uAgain using mirror’s formula
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3uAgain using mirror’s formula1/-20=1/-3u+1/u
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3uAgain using mirror’s formula1/-20=1/-3u+1/uu=-40/3cm
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3uAgain using mirror’s formula1/-20=1/-3u+1/uu=-40/3cmThe possible values of u are
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3uAgain using mirror’s formula1/-20=1/-3u+1/uu=-40/3cmThe possible values of u are 3/−80 cm and 3/−40 cm.
Case 1. For real imagem=-v/u=-3v=3uUsing mirror’s formula1/f=1/v+1/u1/-20= 1/3u+1/uu=-480/3Case 2. For virtual imagem= u/−v =+3v=-3uAgain using mirror’s formula1/-20=1/-3u+1/uu=-40/3cmThe possible values of u are 3/−80 cm and 3/−40 cm.Hence, this is the answer.
I hope you may helps this answer...
Similar questions