Question

find the position ,nature and size of the image formed by a convex lens of focal length 12 centimeter of an object 5 centimeters high placed at a distance 20 cm from it

Answer 1

using the lens law

$= 1 \div 12 - 1 \div 20 = 1 \div x \\ = 10 \div 120 - 6 \div 120 \\ = 4 \div 120 \\ = 1 \div 30 \\ 30 = x$
thus the image is 30 cm behind the lens.
the image is erect and virtual because the object is between the focus and centre of curvature.

using the formula for magnification if image
$30 \div 20 = 3 \div 2$
the image is enlarged

Answer 2

Explanation:

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