find the position nature and size of the image of an object 3 cm high is placed at distance of 9 cm from a concave mirror of focal length 18 cm
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Answer:
Explanation:
1/f = 1/v+1/u
so, 1/18=1/v+1/9
by solving it we get 1/v= -1/18
v= -18 it is position
size: m= -v/u
m=2 ans.
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