Find the position, nature and size of the image of an object 3 cm high placed at a distance of 9 cm from a converging mirror of focal length 18 cm. Draw a neat ray diagram to show this.
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u=−12cm
f=+8cm
ho=+3cm
Using mirror formula,
v1+u1=f1
v1+−301=81
v1−301=81
v1=81+301
v1=603+2
v1=605=121
v=+12cm
Therefore, the image will be formed at a distance of 12cm behind the mirror.
m=um−v=−30m−12=+0.4
m=hohi
0.4=hohi
0.4=1hi
hi=+0.4cm
Therefore, the image formed is diminished in size.
u=−12cm
f=+8cm
ho=+3cm
Using mirror formula,
v1+u1=f1
v1+−301=81
v1−301=81
v1=81+301
v1=603+2
v1=605=121
v=+12cm
Therefore, the image will be formed at a distance of 12cm behind the mirror.
m=um−v=−30m−12=+0.4
m=hohi
0.4=hohi
0.4=1hi
hi=+0.4cm
Therefore, the image formed is diminished in size.
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