Find the position, nature and size of the image of an object 4 cm high placed at a
distance 10 cm from a concave mirror of focal length 20 cm.
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Answer:
see below
Explanation:
u= -10cm
f=-20cm
h=4cm
v=?
H(height of image)=?
1/v + 1/u = 1/f
1/v + 1/-10 = 1/-20
1/v = -1/20+2/20 (after simplification)
1/v = 1/20
v=20cm
m=-v/u=H/h
-20/-10=H/4
H=8
As v and H are positive, the image formed is virtual and enlarged(H>h)
If you have more doubts ask me or refer sign convention,
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