Find the position, nature and size of the image of an object 3 cm high placed at a distance of 9 cm from a converging mirror of focal length 18 cm. Draw the ray diagram for the image formation.
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Answer:
u=-9, f=-18
1/v+1/u=1/f
1/v=-1/18+1/9=1/18
v=18
positive sign shows that the image is virtual and behind the mirror.
height of the image/height of the object=v/u
height of the image =(18/9)×3=6cm
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